We have learned about finding the volume for 3- dimensional shapes. To find the volume of a pyramid you use the formula V=1/3Bh. B is the area of the base and h is the height. To find the volume of a cone you use the formula V=1/3Bh or V=1/3π^2h. B is the area of the base, h is the height of the cone, andr is the radius of the base. To find the volume of a prism you use the formula V=Bh. B is the area of the base and h is the height of the prism. To find the volume of a cylinder you use the formula V=πr^2h. R is the radius of the base and h is the height of the cylinder. I think finding the volume of a prism is the easiest and finding the volume of a cone is the hardest.

The formula for finding the surface area of a pyramid is S=1/2Pl+B. P is the perimeter of the base, l is the slant height and B is the are of the base. To find a cone the formula is L= πrl and S=πrl+πr^2. R is the radius and l is the slant height. To find the surface are of a prism the formula is S=Ph+2B. The P is the perimeter and B is the base. To find the area of the base you use (l•h). To find the area of triangle you use 1/2(b•h). To find the surface area of a cylinder you use 2πrh+ 2πr^2. The r stands for radius and h is the height. I think the easiest one to solve is a prism. I think the cone is the hardest to solve.

1• a) NK is half of 34 as diagonals bisect each other. b) JL is twice of 11 because diagonals bisect each other. c) We can find out KL using Pythagorean theorem. d) JKM is 44 as diagonals bisect angles also. e) JML is 88 as opposite are congruent. f) We can find out MLK by subtracting 88 from 180 as consecutive angles are supplementary. g) MNL is 90 as diagonals in rhombus are perpendicular. h) KJL is 46 because it is equal to MLJ.

2 • a) All sides are congruent in a square and ZY is equal to WZ which is 24. b) WY is 33.9 we can find out using Pythagorean theorem. c) RX would be half of 33.9 which is 16.95 because diagonals are equal. d) WRZ is 90 as ZWR and WZR are 45. e) XYZ is 90 because all the angles in the square are 90. f) ZWY is 45 as it’s angle was bisected by diagonal.

3 • Two angles are congruent so they are set equal. You find x and plug in the value and then find FCD.

A rhombus is a parallelogram with all four sides congruent. If a parallelogram is a rhombus, then its diagonals are perpendicular. A rhombus has all the properties of a parallelogram. If a parallelogram is a rhombus, then each diagonal bisects a pair of opposite angles. There are 2 theorems are for rhombi.

A trapezoid is a quadrilateral with exactly one pair of parallel sides. The sides are called bases. The non parallel sides are called legs. The base angles are formed by the base and one of the legs. If a trapezoid is isosceles, then each pair of base angles is congruent.

The sum of the measures of the exterior angles of a polygon is always 360°. The sum of interior angles side are (n-2)180. The convex is angles that point outside of the shape. The concave is angles that point inside of the shape. The interior angle of a regular polygon is s/n.

A parallelogram is a four-sided plane rectilinear figure with opposite sides parallel. The diagonals of a parallelogram bisect each other. Opposite sides and opposite angles are congruent. Consecutive angles are supplementary. Each diagonal of a parallelogram separates it into two congruent triangles.

The sum of the measures of the exterior angles of a polygon is always 360°. The sum of interior angles side are (n-2)180. The convex is angles that point outside of the shape. The concave is angles that point inside of the shape. The interior angle of a regular polygon is s/n.

A parallelogram is a four-sided plane rectilinear figure with opposite sides parallel. The diagonals of a parallelogram bisect each other. Opposite sides and opposite angles are congruent. Consecutive angles are supplementary. Each diagonal of a parallelogram separates it into two congruent triangles.

I enjoyed my spring break and I did many different things. The first thing I did was go to birmingham and to the pool. In birmingham, I went to Urban Air and shopping. After that I came back home and went to work. In the middle of spring break I went to Destin for 2 days. There I went to the beach and the outlet mall. Towards the end of spring break I went to Atlanta. In Atlanta I went to Atlantic Station and Phipps Plaza. In Phipps Plaza I also met Jacquees. In conclusion, I traveled alot during my spring break and spent all my money.

1. The acr is minor. I know this because its less than 180. I solved this problem by adding 80+50 which equals 130. I need 180 so i subtracted 180-130. My answer was 50. I checked my work by adding the whole circle and it was 360.

2. The arc is minor. I know this because its less than 180. I solved this problem by subtracting 180-100. My answer was 80. I checked it to by adding to make sure it equals 360.

3. This arc is minor. I know this because its less than 180. I solved this problem by adding 80 and 50. My answer was 130.

4. This arc is a semicircle. I know this because its on a diameter. It also equals 180. I know its 180 because it’s a straight line.

5. I had to find the radius and diameter of a circle with the given circumference of 38m. The radius problem will be r=38/2π and the diameter problem will be 38=dπ. For the radius problem, I divided 38 by 2π and got 6.048. For the diameter problem, I divided π on both sides and got 12.096.

6. You are solving for x by simply setting the equations equal to each other. First, I set up the problem 9x-78=3x. Next, I subtracted 9x on both sides to get -78 by itself and get -6. Then, I divided both sides by -6 and got X = 13.

7. I set up the problem 3x-23=2x+2. Next, I subtracted 2x on both sides and also add 23 to 2 and got X=25.

8. I labeled my triangle and identified what I am solving. I am looking for b². I then substituted a² with 8² and c² with 17². Then, I squared 8 and 17 to the second power. Then I subtracted 289 & 64 and got 225. Since I am solving for x and not x² we are going to take the square root of 225 and x² and get X = 15.

9. The formula I need to use is m<1= 1/2(mAB + mAC). The first thing I need to do is plug our numbers into the formula m<y= 1/2(105-63). Then I am going to subtract 105 & 63 and get 42. Next, I am going to multiply 1/2 & 42 and my answer is 21.

10.  The formula I need to use is a(a+b)=c(c+d). I plugged in my numbers into the formula 6(6+x+3)= 6(6+4x). Then I combined like terms in the parentheses. It’s now 6(9+x)= 6(6+4x). Then i distributed 54+6x=36+24x. Then I subtracted 6x on both sides and got 18x and also subtract 36 on both sides and got 18. Then I divided 18x on both sides and my answer is 1.

This week in class we learned about secant and special secants. A secant is a line that intersects a circle at exactly 2 lines. Theorm 10.12 states if 2 secants or chords intersect of a circle then the measure of an angle for is 1/2 the sum of the measures. Theorm 10.14 states if a secant and a tangent intersect at the point of tangency then the measure of each angle formed is 1/2 of the intercepted acr. Theorm 10.15 states if 2 chords intersect in a circle then the products of the lengths of the chord segments are equal. We were also introduced to new vocabulary words which are chord segment, secant segment, external secant segment , and tangent segment. In conclusion, I learned alot of new topics this week in class and I need more practice.

This week in class we learned about tangents. A tangent is a line in the same plane as a circle that intersects the circle in one point. This is called the point of tangency. A common tangent is a line, ray, or segment that is tangent to two circles in the same plane. Theorm 10.10 states in a plane, a line is tangent to a circle if and only if it is perpendicular to a radius drawn to the point of tangency. Theorm 10.11 states if two segments from the same exterior point are tangent to a circle then they are congruent. In conclusion, for any tangent line there is a perpendicular radius.